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Definition: This calculator determines the electrical current (in amps) required for a motor based on its horsepower rating, operating voltage, efficiency, and power factor.
Purpose: It helps electricians, engineers, and technicians properly size electrical circuits and components for motor applications.
The calculator uses the formula:
Where:
Explanation: The formula converts horsepower to watts (1 HP = 746 watts), then divides by the product of voltage, efficiency, and power factor to account for real-world electrical losses.
Details: Accurate current calculation ensures proper wire sizing, circuit breaker selection, and prevents electrical system overloads.
Tips: Enter the motor's horsepower rating, operating voltage, efficiency (default 0.9), and power factor (default 0.8). All values must be > 0.
Q1: Why 746 in the formula?
A: 1 horsepower equals 746 watts, which converts mechanical power to electrical power.
Q2: What's a typical efficiency value?
A: Standard motors typically have 85-95% efficiency (0.85-0.95). High-efficiency motors may reach 0.96.
Q3: What affects power factor?
A: Induction motors typically have 0.8-0.9 PF at full load. It varies with motor load and design.
Q4: Should I use line-to-line or line-to-neutral voltage?
A: For 3-phase calculations, use line-to-line voltage. For single-phase, use the actual circuit voltage.
Q5: How does this differ for 3-phase motors?
A: For 3-phase, multiply the denominator by √3 (approximately 1.732) for accurate calculation.